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Set Theory and Venn Diagrams questions for IPMAT, with solutions

10 free Set Theory and Venn Diagrams practice questions for IPMAT Indore, Rohtak and JIPMAT, each with the answer and a full worked solution. No sign-in. Try each one first, then open the solution. The lessons for this chapter are in Set Theory and Venn Diagrams on Learn.

  1. Question 1Multiple choiceWritten by IPMATwaySet Algebra and Power Sets

    Consider the following statements.

    Statement I: The empty set is a subset of every set.

    Statement II: {∅}\{\emptyset\} is an empty set.

    Which of the following is correct?

    1. A.Statement I is false but Statement II is true
    2. B.Both Statement I and Statement II are false
    3. C.Statement I is true but Statement II is false
    4. D.Both Statement I and Statement II are true
    Show the answer and solution

    Answer: C. Statement I is true but Statement II is false

    Every element of ∅\emptyset (there are none) lies in any set, so ∅⊆A\emptyset\subseteq A. {∅}\{\emptyset\} contains one element, so n=1n=1.

  2. Question 2Multiple choiceWritten by IPMATwaySet Algebra and Power Sets

    The number of proper subsets of a set with 55 elements is

    1. A.3030
    2. B.3131
    3. C.2525
    4. D.3232
    Show the answer and solution

    Answer: B. 3131

    All subsets 25=322^5=32; a proper subset excludes the set itself: 3131.

  3. Question 3Multiple choiceWritten by IPMATwayTwo-Set Venn Problems

    Consider the following statements.

    Statement I: If n(A)=10n(A)=10, n(B)=15n(B)=15 and n(A∪B)=20n(A\cup B)=20, then n(A∩B)=5n(A\cap B)=5.

    Statement II: If A⊂BA\subset B, then n(A∪B)=n(A)n(A\cup B)=n(A).

    Which of the following is correct?

    1. A.Statement I is true but Statement II is false
    2. B.Statement I is false but Statement II is true
    3. C.Both Statement I and Statement II are false
    4. D.Both Statement I and Statement II are true
    Show the answer and solution

    Answer: A. Statement I is true but Statement II is false

    Statement I follows from n(A∩B)=n(A)+n(B)−n(A∪B)n(A\cap B)=n(A)+n(B)-n(A\cup B). Statement II fails whenever BB is strictly larger than AA.

  4. Question 4Type the answerWritten by IPMATwayThree-Set Venn Problems

    In a survey of 200200 students, 120120 study Mathematics, 9090 study Physics and 7070 study Chemistry; 4040 study Mathematics and Physics, 3030 study Physics and Chemistry, 5050 study Chemistry and Mathematics, and 2020 study none of these. The number of students who study all three is

    Show the answer and solution

    Answer: 20

    At least one =200−20=180=120+90+70−(40+30+50)+t=200-20=180=120+90+70-(40+30+50)+t, so t=20t=20.

  5. Question 5Multiple choiceWritten by IPMATwayTwo-Set Venn Problems

    If n(U)=40n(U)=40, n(A)=25n(A)=25 and n(B)=20n(B)=20, the greatest possible value of n(A∪B)n(A\cup B) is

    1. A.2525
    2. B.4545
    3. C.4040
    4. D.55
    Show the answer and solution

    Answer: C. 4040

    The union cannot exceed UU; 25+20=45>4025+20=45>40, so the greatest union is 4040 (with overlap 55).

  6. Question 6Type the answerWritten by IPMATwayThree-Set Venn Problems

    The number of natural numbers less than or equal to 10001000 that are divisible by at least one of 33, 77 and 1111 is

    Show the answer and solution

    Answer: 480

    Singles ⌊10003⌋=333\lfloor\frac{1000}{3}\rfloor=333, 142142, 9090; pairs (multiples of 2121, 3333, 7777) 4747, 3030, 1212; all three (multiples of 231231) 44. Total 480480.

  7. Question 7Multiple choiceWritten by IPMATwayThree-Set Venn Problems

    The number of natural numbers not exceeding 10001000 that are divisible by none of 1010, 1515 and 2525 is

    1. A.854854
    2. B.146146
    3. C.806806
    4. D.794794
    Show the answer and solution

    Answer: A. 854854

    Overlaps are multiples of the LCMs: 3030 (3333), 7575 (1313), 5050 (2020); all three: 150150 (66). So 146146 are divisible by at least one and 854854 by none.

  8. Question 8Multiple choiceWritten by IPMATwayTwo-Set Venn Problems

    A survey shows that 63%63\% of the people watch a news channel and 76%76\% watch another channel. If x%x\% watch both, then

    1. A.x=39x=39
    2. B.x≤39x\le 39
    3. C.39≤x≤6339\le x\le 63
    4. D.63≤x≤7663\le x\le 76
    Show the answer and solution

    Answer: C. 39≤x≤6339\le x\le 63

    Overlap at least 139−100=39139-100=39; at most the smaller group, 6363.

  9. Question 9Multiple choiceWritten by IPMATwaySet Algebra and Power Sets

    How many subsets of {1,2,…,8}\{1,2,\dots,8\} contain at least one odd number and at least one even number?

    1. A.224224
    2. B.225225
    3. C.240240
    4. D.192192
    Show the answer and solution

    Answer: B. 225225

    Total subsets: 28=2562^8=256. Subsets with no odd number are subsets of {2,4,6,8}\{2,4,6,8\}: 24=162^4=16 (including the empty set). Subsets with no even number: also 1616. Both bad families contain the empty set, so the union has 16+16−1=3116+16-1=31 subsets. Required count =256−31=225=256-31=225. Equivalently: non-empty subsets of the odds (1515) times non-empty subsets of the evens (1515) =225=225.

  10. Question 10Type the answerWritten by IPMATwaySet Algebra and Power Sets

    How many subsets of {1,2,…,10}\{1,2,\dots,10\} (including the empty set) contain no two consecutive integers?

    Show the answer and solution

    Answer: 144

    Let ana_n count valid subsets of {1,…,n}\{1,\dots,n\}. If nn is not chosen, the rest is any valid subset of {1..n−1}\{1..n-1\}: an−1a_{n-1}. If nn is chosen, n−1n-1 is not, leaving a valid subset of {1..n−2}\{1..n-2\}: an−2a_{n-2}. So an=an−1+an−2a_n=a_{n-1}+a_{n-2}, with a1=2a_1=2 (∅,{1}\emptyset,\{1\}) and a2=3a_2=3. Continuing: a3=5,a4=8,a5=13,a6=21,a7=34,a8=55,a9=89,a10=144a_3=5,a_4=8,a_5=13,a_6=21,a_7=34,a_8=55,a_9=89,a_{10}=144.