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Statistics questions for IPMAT, with solutions

10 free Statistics practice questions for IPMAT Indore, Rohtak and JIPMAT, each with the answer and a full worked solution. No sign-in. Try each one first, then open the solution. The lessons for this chapter are in Statistics on Learn.

  1. Question 1Type the answerWritten by IPMATwayMean, Median and Mode

    The mean of 1010 observations is 1212. If each observation is doubled and then decreased by 33, the mean of the new observations is

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    Answer: 21

    If every xx becomes 2x−32x-3, the mean becomes 2xˉ−32\bar x-3.

  2. Question 2Type the answerWritten by IPMATwayMean, Median and Mode

    If the mean of the numbers aa, a+2a+2, a+4a+4, a+6a+6 and a+8a+8 is 2020, their median is

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    Answer: 20

    5a+20=100⇒a=165a+20=100\Rightarrow a=16; the numbers are 16,18,20,22,2416,18,20,22,24 with median 2020.

  3. Question 3Type the answerWritten by IPMATwayMean, Median and Mode

    In a group of 2020 students, 33 scored 4040, 55 scored 5050, 77 scored 6060 and 55 scored 7070. The median score is

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    Answer: 60

    Cumulative frequencies locate both middle positions in the 6060 group.

  4. Question 4Type the answerWritten by IPMATwayRange, Variance and Deviation

    The standard deviation of 2020 items is 1010. If each item is decreased by 11, the standard deviation of the new items is

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    Answer: 10

    Shifting all data by a constant does not change the spread.

  5. Question 5Type the answerWritten by IPMATwayRange, Variance and Deviation

    The variance of a set of observations is 1616. If every observation is multiplied by 33, the variance of the new set is

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    Answer: 144

    SD scales by 33 (from 44 to 1212), variance by 99.

  6. Question 6Type the answerWritten by IPMATwayMean, Median and Mode

    For three real numbers, the sum of the maximum and the minimum is 4040 and the median exceeds the mean by −2-2 (that is, the mean exceeds the median by 22). The median of the three numbers is

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    Answer: 17

    Sum =40+m=40+m; set mean minus median equal to 22 and solve.

  7. Question 7Type the answerWritten by IPMATwayMean, Median and Mode

    The mean of 1111 numbers is 5050. If the mean of the first six numbers is 4848 and that of the last six numbers is 5454, the sixth number is

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    Answer: 62

    The two groups of six overlap in the sixth number, which is therefore counted twice in the combined sums.

  8. Question 8Type the answerWritten by IPMATwayMean, Median and Mode

    The mean of 2525 observations is 4040. It was found that an observation 6464 had been wrongly included; after removing it, the mean of the remaining observations is

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    Answer: 39

    Remove the value from the total and divide by 2424.

  9. Question 9Type the answerWritten by IPMATwayMean, Median and Mode

    The mean of 100100 observations is 5050. If the mean of the first 6060 observations is 4444, the mean of the remaining 4040 observations is

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    Answer: 59

    Remaining total divided by the remaining count.

  10. Question 10Type the answerWritten by IPMATwayMean, Median and Mode

    The sum of the deviations of 1515 observations from the value 4040 is 3030. The mean of the observations is

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    Answer: 42

    The mean equals the assumed value plus the mean deviation from it: 40+30/1540+30/15.